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Let the equal sides of the isosceles triangle be x. Given: Base = 20 cm, sum of the other two sides = 30 cm, so 2x = 30, x = 15 cm. Now, the altitude divides the triangle into two right-angled triangles. Using Pythagoras' theorem for one of the right-angled triangles: x² = (20/2)² + h² 15² = 10² + h² 225 = 100 + h² h² = 125 h = √125 = 5√5 cm. Area of the triangle = 1/2 × base × height Area = 1/2 × 20 × 5√5 Area = 50√5 cm². Correct option: B) 50√5 cm².
If x 2 – 15x + 51 = 0, then determine the value of (x – 5) + {1/(x – 5)}.
√(92×8 ×52+700) = ?
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