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Since, ABC is a triangle, So, ∠ A + ∠ B + ∠ C = 180o .......... (I) Also, ∠ A - ∠ C = 8o .......... (II) On subtracting equation (II) from equation (I), we have; 2 ∠ A + ∠ B = 188o .......... (III) Also, ∠ A - ∠ B = 16o ........ (IV) On adding equation (III) and (IV), we have; 3 ∠ A = 204o Or, ∠ A = 68o So, ∠ B = 68o - 16o = 52o
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