Question
The area of an equilateral triangle increases by 16β3
square units when the length of each side is increased by 4 units. What is the original perimeter of the triangle?Solution
Let length of each side of the equilateral triangle = βxβ units After increment, length of each side of the equilateral triangle = (x + 4) units According to the question, (β3/4) Γ (x + 4)2Β β (β3/4) Γ x2Β = 16β3 Or, (β3/4) Γ [(x + 4)2Β β x2)] = 16β3 Or, (1/4) Γ [x2Β + 16 + 8x β x2)] = 16 Or, (1/4) Γ (16 + 8x) = 16 Or, 16 + 8x = 64 Or, 8x = 48 Or, x = 6 Therefore, original perimeter of the equilateral triangle = 3x = 6 Γ 3 = 18 units
36895 - 4256 - 2233 = ?Β
Find the simplified value of the following expression:
[{12 + (13 Γ 4 Γ· 2 Γ· 2) Γ 5 β 8} + 13 of 8]
- Simplify:

(21 X 5) + ? = (480 - 120) Γ· 3
What will come in the place of question mark (?) in the given expression?
34 X 11 - ? + 36 = 3 X 75 + 125
- What will come in the place of question mark (?) in the given expression?
(β1089 + 47) X 4.5 = ? - β256 X 10 62 + 43 + 625(1/4) - ? = 102
625 Γ (?% Γ· 125) = 250% of 10
3 β8 Γ β36 Γ 13 = ? Γ β169
81 Γ· 0.09 Γ 1.4 β 1223=?