If A + B = 450 , then the value of 2(1 + tanA) (1 + tanB) is:
A +B=45 ∘ Ontakingtanboth s i d e s , tan (A+B)=tan (45 ∘ ) tanA + tanB 1−tanA tanB = 1 tan A + tan B = 1 − tan Atan B tanA+tanB +tanAtanB = 1 --- (1) N o w , 2(1+tanA)(1+tanB ) =2(1+tanA+tanB+tanAtanB ) From the eq(1), =2(1+1) = 4
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