If A lies in the first quadrant and 6 tan A = 5, then the value of 8 sin A−4 cos A / cos A+2 sin A is :
6 tan A = 5 tan A = 5 / 6 8 sin A−4 cos A / cos A+2 sin A = cosA(8 tan A−4) / cos A(1+2 tan A) = 8 tan A−4 / 1+2 tan A Put the value of tan θ, = (8 × 5 / 6 −4) / (1 + 2 × 5/6) = (20/3 – 4) / (1 + 5/3) = (8/3) /(8/3) = 1
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