Question

    A 3 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 1 Correct Answer Incorrect Answer
    D 1/2 Correct Answer Incorrect Answer

    Solution

    Above expression can be written as = with the help of (a + b)3  = a3  + b3  + 3ab (a + b) a2  – b2  = (a + b) (a – b) (a + b)2  = a2  + b2  +2ab = (cos2  θ + sin2  θ)3  / cosec θ sec θ [sin2  θ  + cos2 θ + 2sin θ cos θ – 1] = 1 / 1/sin θ cos θ [1 + 2sin θ cos θ – 1] = 1/2

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