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Sec²A – Tan²A = 1 (SecA – TanA) (SecA + TanA) = 1 (SecA – TanA) (2√2 + 9) = 1 (SecA - TanA) = 1/(2√2 + 9) SecA – TanA = 9 - 2√2 ………………(i) SecA + TanA = 9 + 2√2 ……………… (ii) By solving the two equations we get, 2SecA = 18 SecA = 9 CosA = 1/9 Sin²A + Cos²A = 1 Sin²A + 1/81 = 1 Sin²A = 1 - 1/81 Sin²A = 80/81 SinA= (4√5)/9 SinA + CosA = (4√5)/9+ 1/9 SinA + CosA = (1+4√5)/9
1199.98 ÷ 40.48 × 20.12 = ? × 3.16
85% of 1740 + 30² = ? + 1575 ÷ 15
12.023 + 32.05 × 16.08 – 84.04% of 2400 = 56.06% of ?
386.99 + 397.99 + ? - 232.02 = 35.02 × 31.99
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
(√899.69 + 49.83% of 640.24)² - (7/8 of 479.79) = ?
√440.98 + (17.95% of 249.96 – 12% of 99.99) + (7.12)2 = ?
25.05% of 220.05 – 10.15% of 119.99 × 2.02 = ?
?2 = 159.97% of 65.004 + 319.98 ÷ 15.99 - 24