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tan B = 70/AB tan 30˚ = 70/AB => 1/√3 = 70/AB AB = 70√3 Now, => AD = AB - BD => AD = 70√3 - 140√3/3 => AD = 70√3/3 Now, => tan θ = 70/(70√3/3) = 3/√3 => tan θ = √3/1 = tan 60˚
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