Question
If (5sinx - cosx) = 2β2sinx, then find the value of
'tanx'Solution
(5sinx - cosx) = 2β2sinx Dividing both side with sinx, 5 β cotx = 2β2 cotx = 5 - 2β2 tanx = 1/(5 - 2β2) tanx = (5 + 2β2)/{( 5 - 2β2) Γ (5 + 2β2)} = (5 + 2β2)/17
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