sin 28° = 15/17 = perpendicular/hypotenuse So perpendicular = 15 & hypotenuse = 17 so base = 8 But for angle 62° which is complimentary of 28°, perpendicular = 8 & base = 15. So tan 62° = perpendicular/base = 8/15 Alternate Method sin 28° = 15/17 or cos (90°-28°) = 15/17 or cos 62° = 15/17 -----(1) Squaring on both sides, we will get cos2 62° = 225/289 or (1 - sin2 62°) = 225/289 or sin2 62° = 1 - 225/289 = 64/289 = `(8/17)^2` So sin 62° = 8/17 ----(2) Hence tan 62° = sin62°/cos62° = `(8/17)/(15/17)` = `8/15` ` ` ` ` ` ` ` ` ` ` ` `
Statements: B & C, C # D, D @ E, E % F
Conclusions: I. C & F II. E # B
...Statement- 1 - 6#≥9#≥10#≤5#
2 - 7*≤10#˃5*≥6*
Conclusions:
1) 7* > 6*
2) 6* > 7*
3) 6# ≤ 5#<...
In the following question the relationship between different elements are given in the statements followed by two conclusions I, and II. Read the state...
Statements:
R ≤ A ≤ B > C = X < J < K = L
Conclusions: I. R ≤ B II. L > C ...
Statements: B ≤ I; E = D; H > F; C ≤ H; I = D; A ≤ B; H < E
Conclusions:
(i) I > F
(ii) B ≤ H
(...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and th...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statements:
A < C < F; G > H = F < K < L
Conclusions:
I). G > K
II). K ≥ G
What is the place of question mark (?) in the given expression does the expression L < I and W > L is definitely true?
W = P ≥ M ? L ; P ≤ I
Statements: B > D = H > G < J ≤ K > L < I
Conclusion
I: B ≥ G
II: K > G
