Answer-Solve for x in the interval [0, 2π]: 2 sin²x + 3 sinx - 2 = 0.

Let sin x y. Then, 2y 3y - 2 0. Solving, we get y -2 or y 12. Thus, sin x 12 gives x 6, 56. Correct answer a

Question

Solve for x in the interval [0, 2π]: 2 sin²x + 3 sinx

- 2 = 0.

A x = π/6, 5π/6

B x = π/4, 3π/4

C x = π/3, 4π/3

D None of these

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