Let the distance of the first car from the base of the building be x, and the distance of the second car be y. For the first car, using tan(30°) = height / distance: tan(30°) = 120 / x 1/√3 = 120 / x x = 120√3 meters. For the second car, using tan(60°) = height / distance: tan(60°) = 120 / y √3 = 120 / y y = 120 / √3 = 40√3 meters. The distance between the two cars is x - y: 120√3 - 40√3 = 80√3 meters. Correct answer: b
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