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Let the height of the building be h meters. Let the initial distance from the building be x meters. From the first position: tan 45° = h/x, 1 = h/x, h = x. From the second position (after moving 10 meters closer): tan 60° = h/(x - 10), √3 = h/(x - 10). Now substitute h = x into the second equation: √3 = x/(x - 10). Solving this equation: x/√3 = x - 10 x(√3 - 1)/ √3 = 10 x = 10 (√3 - 1)/ √3 meters. So, the height of the building h = 10 (√3 - 1)/ √3 meters.
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
The value of [(3√2+2) × (3√2-2)] of 13 + 15 is:
25.6% of 250 + √? = 119
32.5% of 40 + (13)2 + 102 = ?
350% of (450 / 1.5) = ?% of 4200
84% of 800 + 70% of 640 = 14 × ?
(√7225 x √1225)/(√625) = ?
(1/3) + (2/5) + (3/4) + (11/10) = 3 – (?/12)
13/3 – (23/6) = ? – (22/9)