Since, sec2 θ - tan2 θ = 1 Therefore, sec2 θ = 1 + (2/√5)2 = {(5 + 4)/5} = (9/5) Therefore, cos2 θ = (1/sec2 θ) = (5/9) Alternate Solution Given, tan θ = (2/√5) = (perpendicular/base) So, perpendicular = 2 units Base = √5 units So, hypotenuse = √{(22 + ( √ 5)2} = √(4 + 5) = 3 units So, cos2 θ = (Base/hypotenuse) = (√5/3)2 = (5/9)
Consider the following statements about Lonar lake:
1. It is a saltwater lake located in peninsular India.
2. The lake was formed due...
The Gopatha Brahmana is linked to which Veda?
In the 24th GST council meeting a decision was taken to implement e-way bill for inter-state transactions across the country from
How frequently is the population census conducted in India?
Which temple was awarded the best ‘Swachh Iconic Place ‘in India?
In which city of India is the UNESCO World Heritage site 'Basilica of Bom Jesus' located?
Dekhnni dance is one of the oldest dance forms of which place?
Mahatma Gandhi Sarbat Vikas Yojna was recently launched in the state of
In which city was the first Multi Purpose Vessel (MPV) for the Indian Navy, named ‘Samarthak’, launched?
In ARR method the decision is to accept the project if ARR is more than the minimum expected rate of return
