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sin 3A sec 6A = 1
Or, sin 3A = (1/sec 6A)
We know that, sec P is the reciprocal of cos P
Or, sin 3A = cos 6A
We know that, cos P = sin (90 - P)
Or, sin 3A = sin (90 - 6A)
Or, 3A = 90 - 6A
Or, 9A = 90
So, 'A' = 10
Required value = cos 6A = cos 60 o = (1/2)
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