If cot2A = tan(A+6Ëš ) Â , find the value of A? Given that 2A and A+6Ëš Â are acute angles.
Always remember that cot & tan are compliment to each other So tan ɵ = cot( 90-ɵ) So it is given that cot2A = tan(A+6˚ ) Hence 2A + A+6˚  = 90˚ So 3A+6˚  = 90˚ or 3A = 90˚ -6˚  =84˚ or A = 
= 28Ëš Â
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