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sin 23° = `12/13` = perpendicular/hypotenuse So perpendicular = 12 & hypotenuse = 13 so base = 5 But for angle 67° which is complimentary of 23°, perpendicular = 5 & base =12. So tan 67° = perpendicular/base = `5/12` Alternate Method sin 23° = `12/13` or cos (90°-23°) = `12/13` or cos 67° = `12/13` -----(1) Squaring on both sides, we will get cos2 67° = `144/169` or (1 - sin2 67°) = `144/169` or sin2 67° = 1 - `144/169` = `25/169` = `(5/13)^2` So sin 67° = `5/13` ----(2) Hence tan 67° = sin67°/cos67° = `(5/13)/(12/13)` = `5/12` ` ` ` ` ` ` ` ` ` ` ` `
3/7 Of 504 ÷ 12 + 17 = √?
436 × 794 – 68210 =? + 85730
(47.5 ÷ 9.5) × (78.5 ÷ 15.7) + 475 = ? + 15% of 150
(?)2 = {(26% of 35% of 3000) ÷ 3} × 91
22.5% of 300 + 32.5% of 4500 =?
25.6% of 250 + √? = 119
375% of 320 - 80% of 40 ÷ √256 = ?
1280 ÷ 8 + 490 ÷ √49 + ? = 150 * 2