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9 sinx + 40 cosx = 41 or (9/41) sinx + (40/41) cosx = 1 ---(1) Now comparing equation with sin2 x + cos2 x = 1 ; We can say that, sinx = 9/41 and cosx =40/41 Hence tanx = sinx/cosx = (9/41)/(40/41) = 9/40 ` `
(〖(0.4)〗^(1/3) × 〖(1/64)〗^(1/4) × 〖16〗^(1/6) × 〖(0.256)〗^(2/3))/(〖(0.16)〗^(2/3) × 4^(-1/2) ×〖1024〗^(-1/4) ) = ?
(18 2 – 17 2) x (1/5) + ? = 148
The value of 43-3× (4×6+12/3 ×6-4×5) +4?
4.56 + 56.4 + 64.5 = ? + 10.46
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
(292 – 141) ÷ 5 + (40 ÷ 2) + 23 = ?
(125 × 12 × √8100) ÷ 150 = ?
?2 + 114 - 48 ÷ 2 × 5 = 163
? (1/2) = 236 – 25 × 18/2 + 396 ÷ 22
The value of (40 + 3/4 of 32) /[37 + 3/4 of (34-6)] is: