Question
If 9 sinx + 40 cosx = 41 then find tanx.
Solution
9 sinx + 40 cosx = 41 or (9/41) sinx + (40/41) cosx = 1 ---(1) Now comparing equation with sin2 x + cos2 x = 1 ; We can say that, sinx = 9/41 and cosx =40/41 Hence tanx = sinx/cosx = (9/41)/(40/41) = 9/40 ` `
More Trigonometry Questions
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