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Start learning 50% faster. Sign in now(3Sinθ+2 Cosθ )/(3 Sinθ-2Cosθ) By dividing numerator and denominator by cosθ (3 × Sinθ/Cosθ+2 × Cosθ/Cosθ)/(3 × Sinθ/Cosθ-2 × Cosθ/Cosθ) = (3 tanθ+2)/(3 tanθ-2) Put the value of Tanθ = (3 × 8/3+2)/(3 × 8/3-2) = (8+2)/(8-2) = 10/6 = 5/3 Alternate Solution: sinθ/Cosθ = 8/3 So by putting Sinθ=8 & Cosθ = 3 in the required ratio, We will get (3Sinθ+2 Cosθ )/(3 Sinθ-2Cosθ) = (3*8+2*3)/ (3*8 - 2* 3 ) = 30/ 18 = 5/3
20 25 54 165 662 ?
...12 13 30 �...
92, 51, 21, 13.5, x, 4.25
find the value of (10x + x -5)?
4 12 ? 144 544 2112
...-3 -10 -40 -185 -905 -4500
-4 a b c d e
Find the value of d.
...2, A, 9, B, 6, C, 13, D, ?
720 ? 240 180 144 120
...16, 8, 8, ?, 24, 60
13 15 ? 63 143 293
...6 7 15 46 185 ?
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