Question
A is twice as good a workman as B and together they
finish a piece of work in 14 days. The number of days taken by A alone to finish the work isSolution
Let daily work done of A =2units & Daily work done of B =1units So (A+B)’s 1 day work = 2+1 = 3units; Total work done by A & B in 14 days = 14×3 =42 units So A alone can complete job in = 42/2 = 21 days
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