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ATQ, 121 – (3 × 1) = 118 118 + (3 × 2) = 124 124 – (3 × 3) = 115 115 + (3 × 4) = 127 127 – (3 × 5) = 112 Therefore, 124 should come in place of 122. The given series follows alternate addition and subtraction of consecutive multiples of 3.
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