Question
There are two wrong number series given in question and
three relationships has been derived from that you have to answer the correct relationship between the two wrong numbers. I) 449, 452, 461, 476, 497, 520 II) 24, 36, 90, 260, 1417.5, 7796.25 i) Difference between two wrong numbers is 44 ii) Both the numbers are divisible by 11 iii) Ratio of two wrong numbers is 2: 1Solution
Answer: E Series I, 449 + (3 * 1) = 452 452 + (3 * 3) = 461 461 + (3 * 5) = 476 476 + (3 * 7) = 497 497 + (3 * 9) = 524 The Wrong term is 520 Series II, 24 * 1.5 = 36 36 * 2.5 = 90 90 * 3.5 = 315 315 * 4.5 = 1417.5 1417.5 * 5.5 = 7796.25 The Wrong term is 260 i) Difference = 0, wrong ii) Both the numbers are divisible by 11, wrong iii) Ratio of two wrong numbers is 2: 1, true.
- If (x + y + z) = 14 and (xy + yz + zx) = 50, then find the value of (x² + y² + z²).
If x, y and z are real numbers such that (x-5)2+(y-7)2+(z-9)2= 0 then (x+y+z) is equal to
If cos(A - B) = √3/2 and cot(A + B) = 1/√3, where A - B and A + B are acute angles, then (2A - 3B) is equal to:
If x4 + 1/(x4) = 194 , , then find the value of 1/(x3 ) + x3 ?
...If (x + y) = 40, then find the value of (x - 15)5 + (y - 25)5.
What is the value of (a² + b²+4c²- ab-2bc-2ca) (a + b+2c):
A sum of Rs. 25,000 is invested in SIP 'G' which offers 7% p.a. simple interest for 7 years. The interest received from SIP 'G' is invested in SIP 'H' w...
ABCD is a cyclic quadrilateral in which AB =16.5 cm. BC = x cm. CD= 11 cm. AD 19.8 cm, and BD is bisected by AC at O. What is the value of x?
Atul has Rs.500 with him. He invested 30% of the amount at 5% p.a. for 6 years and rest at 20% p.a. for 4 years. Find the sum of simple interests receiv...