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    Question

    There are eight cars A, B, C, D, E, F, G and H. Each

    car has a different price. Price of C is more than that of A and D. Price of atleast two cars is less than A. Price of F is more than that of G and H. Price of D is less than G, but more than E. Price of B is less than H, but more than G. Price of atleast four cars is more than that of C. Which of the following sequence is correct?
    A F > H > B > G > C > A > E > D Correct Answer Incorrect Answer
    B F > H > B > G > C > D > A > E Correct Answer Incorrect Answer
    C F > H > B > G > C > A > D > E Correct Answer Incorrect Answer
    D F > H > G > B > C > A > D > E Correct Answer Incorrect Answer

    Solution

    We have,     Price of C is more than that of A and D, Price of at least two cars is less than A, Price of F is more than that of G and H. Price of D is less than G but more than E. Price of B is less than H but more than G. Price of at least four cars is more than that of C. So the final arrangement –    F>H>B>G>C>A>D>E

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