The logic used here is as follows: For ‘COLD’ written as ‘FLOA’: C + 3 = F O - 3 = L L + 3 = O D - 3 = A For ‘WARM’ written as ‘ZXUJ’: W + 3 = Z A - 3 = X R + 3 = U M - 3 = J Applying the same logic to the word ‘HEAT’: H + 3 = K E - 3 = B A + 3 = D T – 3 = Q So, the code for ‘HEAT’ is KBDQ’. Hence, option 4 is the correct answer.
Statement: F ≥ G > I > E ≤ P, E = S ≥ PÂ
Conclusion: I. F ≥ P          II. G > P
Statements: D > C ≥ A ≤ B = F, G ≤ K < L < C
Conclusion:
I. D > G
II. C > G
III. K ≤ B Â
Statements : C ≤ A < B ≤ D; E < B > F > G; I < H < G
Conclusions :
I. B > I
II. D > H
III. H < B
Statements: C $ O, O% D, A © D
Conclusions:Â
I. A © OÂ
II. D @ CÂ
III. C © A
Statements: I $ N, N # U, U @ E, E & S
Conclusions: I. E & N II. S @ N III. I $ U
...Statements: M > N = W; J < P = N; Y > P
Conclusions:
I. Y > W
II. M < Y
III. J > M
Statements: F = G ≤ H = J ≤ I, K > L > O = I, D > M > F
Conclusions:
I. O ≥ F
II. D > G
III. K > F
Statements: B & A, A # O, O $ Z, Z @ S
Conclusions:
I. Z $ A
II. Z & A
Statements: E = Q > R = Y ≤ Z = N; K = Y; L > R
Conclusion: I. N > L II. N ≤ L
Which of the following symbols should replace (1) and (2) respectively in the given expression in order to make the expression N > P definitely true?