Question
The price of sugar having gone down by 20% one can buy
6.4kg more for Rs 512. Find the ratio between the original and the reduced price (per kg)?Solution
Let the original price by Rs x Reduced price = Rs (80x/100) ∴512/(80 x/100) - 512/x = 6.4 ⇒51200/80x - 512/x = 6.4 ⇒640/x - 512/x = 6.4 =>128/x= 6.4 ∴ x = 128/6.4 = 20 Original price = Rs 20 Reduced price = Rs (80/100) × 20 = Rs 16 ∴ Required ratio = 20:16 = 5:4
What approximate value will replace the question mark (?) in the following?
? –...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(70.03 ÷ 3.03 × 12.02) ÷ 35.03 × 20.02 × 8.08 = ? × (9.09 2.02 – 1.01)Â
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
27.27% of 5501.22 + 12.53% of 158.99 – √ 1599 = ?
35.1% of 1599 = ?–(449.96 ÷ 6.12) × 2
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(√360.99 + 161.14) ÷ 5 × 249.98 = ?
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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