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Volume of the original box = 18 X 15 X 10 = 2700 cm3 New breadth of the box = 15 X 1.2 = 18 cm New height of the box = 10 X 0.8 = 8 cm So, new volume of the box = 18 X 18 X 8 = 2592 cm3 So, percentage reduction in volume = {(2700 - 2592) ÷ 2700} X 100 = 4% Alternate solution Let the length, breadth and height of the cuboid originally be 'l' units, 'b' units and 'h' units, respectively Therefore, original volume of the cuboid = 'lbh' cubic units New breadth of the cuboid = '1.2b' units New height of the cuboid = '0.8h' units New volume of the cuboid = 1.2b X 0.8h X l = '0.96lbh' cubic units Required percentage = {(lbh - 0.96lbh)/lbh} X 100 = 4%
132, 130, 136, 126, 142, 110
15, 30, 30, 20, 10, 8
74, 79, 86.5, 101.5, 109, 124, 141.5
In each of the following giving number series, a wrong number is given. Find out the wrong number?
3023, 3132, 3246, 3356, 3471
72, 36, 54, 135, 470.5, 2126.25
Find the wrong number in given number series.
1960, 1943, 1930, 1915, 1904, 1895
225, 45, 450, 90, 900, 150, 1800
132, 130, 136, 126, 142, 110
13, 24, 69, 272, 1355, 8248
Find the wrong term in the given series below.
159, 160, 81, 244, 62, 318