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Let the total work = L.C.M of 35, 20 and 28 = 140 units Then, efficiency of 'A' = 140 ÷ 35 = 4 units/day Efficiency of 'B' = 140 ÷ 20 = 7 units/day Efficiency of 'C' = 140 ÷ 28 = 5 units/day Work done by 'A' alone in 5 days = 4 X 5 = 20 units So, work done by 'B' and 'C' in 'x' days = 140 - 20 = 120 units So, x = 120 ÷ (7 + 5) = 10
24% of 35% of (5/8) of 2400 = ?
3/7 Of 504 ÷ 12 + 17 = √?
(152 × 24 + 2540)/25 = 44464 ÷ ?
(6630 ÷ 13 + 6120 ÷ 12) ÷ (17 × 3) = ?
2(3/4) of 2880 + 54% of 7520 - ? = 302
(190/38) × (55/5) + (306/18) = ?
2916 ÷ 54 = ? + 27
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
[(120)2 ÷24 ×25] ÷ 250 =?