Question
β(2x - 3) + β(2x + 3) = 3 + β3,Β then value of x
is.Solution
β(2x - 3) + β(2x + 3) = 3 + β3 Squaring on both sides, {β(2x - 3) + β(2x + 3)}2 = (3 + β3)2Β orΒ 2x - 3 + 2x + 3 + 2 β{(2x)2 - (3) 2} = 9 + 3 + 2 x 3 β3 `` ` ` or 4x + 2 β{4x2Β - 9 2} Β = 12 + 6 β3 Β Β So by comparing the constant part of LHS & RHS, 4x = 12 or x = 3
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