Question
β(3x-2)+ β(3x+2) = 4+ 2β5Β then value of x
is.Solution
β(3x-2)+ β(3x+2) = 4+ 2β5 Squaring on both sides,
=
or
or
So by comparing the constant part of LHS & RHS, 6x = 36 or x = 6.
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