Statement:A≤M=T<C; T≥F ;C ≥D>E<G
I. C > F
II.E < C
Combining the inequalities, A≤M=T<C≥D>E<G; F≤M=T<C≥D>E<G
16% of 250 + 32% of 500 = ?
√(2670+ √(1141+ √(260- √(1251- √(637+ √1521) ) ) ) ) =?
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
(7 ÷ 0.125) x (10 ÷ 10/3 ) = ?
360 × 9 ÷ 3 + 120 + 900 ÷ 5 = ?
50 ÷ 2.5 × 64 + ? = 1520
756 + 432 – 361 + ? = 990
(0.125)³÷ (0.25)² x (0.5)² = (0.5)?-3
(1296) -3/4 = ?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)