Statements:
M < N < K ≥ R > S; Y < B < P ≤ N
Conclusions:
I). S > B
II). Y < K
I). S > B (S < R ≤ K > N ≥ P > B) ->False II). Y < K (K > N ≥ P > B > Y) ->True Hence, option d is correct(Only conclusion II is true)
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