Question
If the consonants of the following words are arranged
first, followed by the vowels as per the English alphabetical order and then the consonants are changed to the previous letter and the vowels are changed to the next letter in the English alphabetical series, then what will be the third letter from the right end of each of the words after the rearrangement? I. BRAZIL II. ANGOLAÂ III. EGYPTSolution
I. BRAZIL II. ANGOLA III. EGYPT After arranging the consonants first followed by vowels as per the English alphabetical order, we get: I.  BLRZAI   II. GLNAAO   III. GPTYE After changing the consonants to the previous letter and the vowels to the next letter in the English alphabetical series, we get:  I. AKQYBJ II. FKMBBP III. FOSXF The third letter from the right end of each of the words is: I. AKQYBJ: Y II. FKMBBP: B III. FOSXF: S
(168 ÷ 12 + 19 × 64)/(22+1) = ?
[∛(91125/19683 )- ∛(3375/5832 ) ] × ∛(512/9261) = ? - √(484/3969)
If 1.123 × 3.211 = 3.122 + ______________, then the number in blank space is
20% of 240 + 18% of 200 = ?
- What will come in place of the question mark (?) in the following questions?
180÷3×2+6=? 29% of 400 + 66% of 1100 - 50% of 1200 = ?Â
36 × 15 + 20% 1250 = ? + 296
Solve for ?.
289 + 896 + 144 – 25% of 1100 =?
What will come in the place of question mark (?) in the given expression?
(352 - ?) ÷ 8 = 2.5 X 40 - 444 ÷ 6