Question
If in ‘4798267583’ each digit at the odd place from
the left end remain unchanged while each digit at the even place from the left end is increased by one, then how many such pairs of the digits are there in the number thus formed, which have as many digits in the number both forward and backward direction as they have between them in the number system?Solution
Given number: 4798267583 After rearrangement we get: 4899277593 So, there are 8 such pairs i.e., 89, 25, 79, 35, 37, 57, 59 and 79.
From the given alternatives select the word which cannot be formed using the letters of the given words.
EXAMINATION
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