Question
If in the number '647315368', 1 added to all the odd
numbers, then what is the sum of the digits which are repeating more than two times in the new number thus formed? Note: While taking the sum the repeating digit is to be considered only once.Solution
6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8 6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8 So, the digits that are repeating more than two times are '6' and '4'. So, sum = (6 + 4) = 10.
2(3/4) of 2880 + 54% of 7520 - ? = 302
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
- What will come in place of (?), in the given expression.
(5³ + 3²) × 2 = ? (1225/25) - (192/96) + (50/5) = ?

What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) ÷ 15 X ? = 36 X 30
- What will come in place of (?), in the given expression.
75% of 640 – 20% of 150 = ? `(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
95% of 830 - ? % of 2770 = 650