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The weight of second heaviest box is 59kgs. Only one box is lighter than G _____ > 69 > ____ > _____> _____> G > ____ A is just heavier than F, which is heavier than C. Two boxes have weight between G and A. D is just heavier than E. C is not the lightest person. D > E(69) > A > F > C > G > B The difference between the weight of E and C is 30kgs. E – C = 30 69 – C = 30 C = 69 – 30 = 39. So, C + A = 99 39 + A = 99 A = 99 – 39 = 60. F’s weight will be more than 39 but less than 60.
(74.93% of 640.11 + 3/4 of 359.79)² - (1/3 of 80.87 × 2)² = ?
Find the approximate value of Question mark(?). No need to find the exact value.
(639.78 ÷ 15.96) × 5 + 30.14% of 349.88 – √(224.95) ÷ 5...
? + 163.99 – 103.01 = 24.01 × 6.98
194.95 + 3.98 × 64.99 - ? = (10.99 + 9.02)2
(284.85 ÷ 15.09) x 2.22 + 51.17 = 157.69 - ?
?% of (140.31 ÷ 19.97 × 80.011) = 139.98
(168.24 ÷ 23.98) x 19.81 + ? = 176.33
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65
811.85 ÷ 28.05 + 462.16 – 23.06 × 17.95 = ?