Six persons A, B, C, D, T and U have different marks in a class test. Who has 2nd highest marks?
Statement I: C has more marks than D and T. At least two persons have more marks than C. A has 3rd lowest marks. B doesn’t have the highest marks. D doesn’t have the lowest marks.
Statement II: Three persons have lesser marks than C. Neither B nor U has fewer marks than C. A has more marks than D and T.
From statement I alone, as C has more marks than D and T. At least two persons have more marks than C. A has 3rd lowest marks. B doesn’t have the highest marks. D doesn’t have the lowest marks, so U > B > C > A > D > T Clearly, B has 2nd highest marks. From statement II alone, as three persons have lesser marks than C. Neither B nor U has less marks than C. A has more marks than D and T, so U / B > B / U > C > A > D / T > T / D Either B or U has 2nd highest marks. Data given in statement I alone is sufficient to answer the question.
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