Seven boxes T, U, V, W, X, Y and Z are kept in a seven-storey building such as bottommost box is numbered as 1 and the box immediately above it is numbered as 2 and so on. Which is the fourth box?
Statement I: W is kept in a prime numbered box. V is kept three boxes above W. Z is kept one box above X. Y is kept one box below T. U is kept three boxes below T.
Statement II: X is kept three boxes above Y. U is kept two boxes below Y. Z is kept above X. V is kept above T. W is kept below T.
From statement I, W is kept in a prime numbered box. V is kept three boxes above W. Z is kept one box above X. Y is kept one box below T. U is kept three boxes below T. We get: From statement I alone, we get T is the fourth box. From statement II, X is kept three boxes above Y. U is kept two boxes below Y. Z is kept above X. V is kept above T. W is kept below T. We get: From statement II alone, we get T is the fourth box. Therefore, data given in either statement I or II alone is sufficient to answer the question.
If 32x + 1– 3x= 3x + 3– 32, then values of x are:
27% of 250 – 0.02% of 1000 is equal to:
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?
(360 - ?)/(25% of 96) = 13
(144 ÷ 4)² × (72 ÷ 12)³ = 12 ×? × (25920 ÷10)
12% of 152 + 12% of 150 = ? of 5
The value of [(3√2+2) × (3√2-2)] of 13 + 15 is:
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2