The original series is as follows: _ Y _ X_ Z X _ Z X _ _ X Y _ On observing the series we are unable to infer any pattern. In such questions, it’s more prudent to take help of the options. On checking each option, we find that a pattern indeed emerges when the letters given under option (B) are used to complete the series. The completed series has been represented below: X Y Z / X Y Z / X Y Z /X YZ /X Y Z We can see that the pattern ‘XYZ’ is being repeated in the series given above. Hence, option (2) is the correct answer
A train can cross a man standing on a platform of 250 metres length in 70 seconds and can cross the platform in 87.5 seconds. Find the length of the train.
Two trains of same length are running in parallel tracks in the same direction with speed 84 km/hr and 120 km/hr respectively. The latter completely cro...
Train A running at a speed of 42 km/hr crosses train B in 36 seconds. Find the speed of train B (in km/hr), if the sum of the length of train A and B is...
Time is taken by two trains running in opposite directions to cross a man standing on the platform in 36 seconds and 21 seconds respectively. It took 27...
Train A running at speed of 162 km/hr crosses a platform having twice the length of train in 22 sec. Train B whose length is 760m crosses same platform ...
Train P travelling at 50 km/hr crosses another train Q, having three fourth of its length and travelling in opposite direction at 40 km/hr in 14 seconds...
Train 'A' is 200 meters long and takes 15 seconds to cross a pole. The same train crosses train 'B' (which is 240 meters long) coming from the opposite ...
Train ‘A’ travelling with a speed of 42 km/h can cross a pole in 6 seconds. If the length of train ‘B’ is 10% less than that of train ‘A’ an...
Train ‘A’ running with a speed of 108 km/hr crosses a vertical pole in 8 seconds. Find the time taken by the train ‘A’ to cross a train ‘B’ ...
A train passes a stationary pole in 12 seconds. It takes 15 seconds for the same train to completely overtake a man who is running at a speed of 14.4 k...