Question
If four hats are picked at random, what is the
probability that one is green, two are blue and one is red? A box contains 6 red, 4 blue, 2 green and 4 yellow hats.Solution
Total number of hats = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 4 hats out of 16 = ¹⁶C_4 = (16 × 15× 14 × 13 )/( 4 × 3 × 2 × 1) = 1820 Let E= event of drawing 4 hats so that one is green, two are blue and one is red = n(E) = ²C_1×⁴C_2×⁶C_1= 2 × 6 × 6= 72 ∴ P (E) = (n(E))/(n(S))= 72/1820 = 18/455
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If ‘E # F + D + A * B & C’ is true, then how is D related to C?
How is T related to S?
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Answer the questions based on the information given below.
A ÷ B means ‘A is the mother of B’
A × B means A is the husband of B
If (A @ B) means A is son of B, (A # B) means A is father of B, (A & B) means A is mother of B, (A $ B) means A is brother of B. If R @ S&T # U $ V@ W, ...
‘W + X’, means ‘W is the sister of X’
‘W - X’, means ‘W is the daughter of X’
‘W × X’, means ‘W is the brother...
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