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The correct answer is I . Place value of different letters given in the series. A – 1, E – 5, I – 9, L – 12, Q – 17, U – 21. So, out of the given options I is odd because out of the given alphabets only I’s place value is a perfect square.
476xy0 is divisible by both 3 and 11. The non-zero digits in the hundreds and tens places are respective.
If ‘48b297a54’ is a nine digit number which is divisible by ‘11’, then find the smallest value of (a + b).
If the 6-digit number 589y72 is completely divisible by 8, then the smallest integer in place of y will be:
If the number 1005x4 is completely divisible by 8, then the smallest integer in place of x will be:
What is the value of a so that the seven-digit number 4645a52 is divisible by 72?
How many factors of 23 × 33 × 54 ×91× is divisible by 50 but not by 100?
Find the greatest value of (a + b) such that an 8-digit number 4523a60b is divisible by 15.
A six-digit number 23p7q6 is divisible by 24. Then the greatest possible value for (p + q) is:
21 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 155. Find the smallest part.