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    Question

    Which of the following letter cluster is the odd letter

    cluster?
    A HI Correct Answer Incorrect Answer
    B LF Correct Answer Incorrect Answer
    C DR Correct Answer Incorrect Answer
    D UE Correct Answer Incorrect Answer

    Solution

    In each letter cluster, the product of the positional value of each letter is '72'. Product of the positional value of 'HI' is (8 X 9) = 72 Product of the positional value of 'LF' is (12 X 6) = 72 Product of the positional value of 'DR' is (4 X 18) = 72 Product of the positional value of 'UE' is (21 X 5) = 105 So, 'UE' is the odd letter cluster.

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