Question
The second number in the given number pairs is obtained
by performing certain mathematical operation(s) on the first number. The same operation(s) is/are followed in all the number-pairs except one. Find that odd number-pair.Solution
Second number = First number + (Sum of digits of first number) 46 - 56 = [{46 + (4 + 6)}] = 46 + 10 = 56 62 - 70 = [{62 + (6 + 2) }] = 62 + 8 = 70 85 – 98 = [{85 + (8 + 5) }] = 85 + 13 = 98 37 - 48 = [{37 + (3 + 7)}] = 37 + 10 = 47
A woman lent Rs. 29500 at 13% p.a. compound interest, compounded annually for two years. After two years, the total amount earned by the woman is again ...
- The simple interest on Rs. 1000 at R% per annum for 2 years is Rs. 160. Calculate the interest on Rs. 1400 at (R + 6)% per annum in 2 years.
Rs. 6,000 is deposited in Scheme 'X' which provides compound interest at 8% per annum, compounded annually. Another amount of Rs. 5600 is invested in Sc...
Piyush initially took a loan from Vivek at a simple interest rate of 8% per annum, and after a duration of two years, he repaid the borrowed amount. Sub...
A man buys a car for ₹800,000. He sells it after 3 years at a loss of 15%. If he invests the selling amount in a fixed deposit at an interest rate (si...
The difference between compound interest and simple interest at rate of 18% per annum for 2 years is Rs. 486. Find the simple interest obtained on same ...
What will be the compound interest earned on an investment of Rs. 20,000 over a period of 3 years at an annual interest rate of 12%, compounded yearly?
Vedant borrows Rs.75,000 for 2 yrs at 3% p.a simple interest. He immediately lends it to Abhishek at 5.5% p.a. for 2 yrs at simple interest. How much Ve...
A farmer borrows ₹50,000 at a simple interest rate of 12% per annum. After how many years will the total interest amount to ₹30,000?
A certain sum of money becomes Rs. 1960 in 1 year and 3000 in 3 years at certain rate of simple interest. Find the sum of money invested.
Relevant for Exams:
