Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the letter-cluster that is different.
The logic followed here is: Positional value of 1st alphabet + 3, 2nd alphabet – 2, and 3rd alphabet + 1. PSQR = P (16) + 3 = S (19) – 2 = Q (17) + 1 = R (18) DGEF = D (4) + 3 = G (7) – 2 = E (5) + 1 = F (6) MPNO = M (13) + 3 = P (16) – 2 = N (14) + 1 = O (15) UXTU = U (21) + 3 = X (24) – 4 = T (20) + 1 = U (21) The cluster UXTU is different. Hence, the correct answer is (D).
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