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Logic: Positional value of 1st alphabet – 4, 2nd alphabet + 3, and 3rd alphabet – 2. XTWU → X (24) – 4 ; T (20) + 3 ; W (23) – 2 ; U (21) TPSQ → T (20) – 4 à P (16) + 3 à S (19) – 2 à Q (17) LHKI → L (12) – 4 ; H (8) + 3 ; K (11) – 2 ; I (9) FBED → F (6) – 4 ; B (2) + 3 ; E (5) – 2 ; C (3) (NOT D) Hence, the correct answer is (D).
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