Question
A team of seven members is be selected from ten members
M1, M2, M3, M4, M5, M6, M7, M8, M9 and M10. Criteria for the selection are: M3 and M6 have to be selected together. Either M2 or M5 has to be selected with M7. M9 and M2 cannot be selected together. Neither M7 or M9 can be selected with M8. Either M4 or M6 has to be selected with M1. Which of the following members may be selected?Solution
We have, M5 and M10 are to be selected together, neither M3 nor the M5 can be selected with M9 M8 either M4 or M6 to be chosen, M1 either M5 or M7 is to be selected.  Hence, M8 and M4 is chosen as well M5 and M10 are selected So, the final arrangement  M2, M3, M4, M5, M7, M8, M10
62 + 43 + 625(1/4) - ? = 102
√4096 + √3249 = (?)2
7(3/6) of 534 + 262 = 61800 - ?
- Find the value of the expression:
32 + 6 – 5 × [18 + 10 – 3 × (36 – 21)] 26% of 950 + 50/3% of 7962 = ? Â
What will come in the place of question mark (?) in the given expression?
(437 + ? - 167) x 2.5 = 87531% of 3300 +659 = ?
16 × 14 + 30 × 21 = 14 × ?
Simplify: (23×32) ÷6
∛857375 + ∛91125 = ? + √6889