There are 3 badminton players in each stream -Commerce, Science and Arts. A, B and C are from Commerce. P, Q and R are from Science. J, K and L are from Arts. A team of 4 badminton players are to be sent for a tournament with following conditions:

(i) There must be at least one student from each stream.

(ii) P will not go with Q or R.

(iii) A and C will always go together.

(iv) K and L will always go together.

Which of the following combinations of players is a possible combination for the tournament?

Solution

Let's analyze the given conditions: (i) There must be at least one student from each stream. This means we need to select one player from each stream - Commerce, Science, and Arts. (ii) P will not go with Q or R. P cannot be in the same team as Q or R. (iii) A and C will always go together. A and C must be in the same team. (iv) K and L will always go together. K and L must be in the same team. Based on these conditions, let's analyze the options: 1. A, C, P, and J This satisfies all conditions. A and C are together, P is not with Q or R, and J represents Arts. 2. A, Q, R, and J This violates condition (ii) because P cannot go with Q or R. 3. B, Q, J, and K This doesn't satisfy condition (i) because there's no player from the Commerce stream. 4. B, P, R, and J This violates condition (iii) because A and C must always go together. So, the only possible combination is option 1: A, C, P, and J.