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The correct answer is B
One of the roots of the equation p2 - (y+3)p + 6y = 0 is cube of 2. What will be the difference of other root and 'y'.
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
I. 12x2 + 22x + 8 = 0
II. 4y2 - y − 3 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. x2 - x - 56 = 0
II. y2 - 20y + 96 = 0
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. x ² + 5 x + 6 = 0
II. y²+ 7 y + 12= 0
...I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I). p2 - 20p + 51 = 0,
II). 2q2 - 7q + 6 = 0