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I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 2x2- 5x - 33 =0
II. 2y2+ 5y - 25 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
I. y/16 = 4/y
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
LCM of 'x' and 'y' is 30 and their HCF is 1 such that {10 > x > y > 1}.
I. 2p²- (x + y) p + 3q = 0
II. 2q² + (9x + 2) = (3x + y) q
I. x3 = 1728
II. y2 – 15y + 56 = 0
I. 6p2 – 7p = 5p – 7p2 + 25
II. 11q2 – 63q + 90 = 0
I. x² – 44x + 468 = 0
II. y² – 30y + 216 = 0
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
I. 8x2- 2x – 15 = 0
II. 12y2- 17y – 40 = 0