Who celebrated his birthday between Y and G?
At most two people celebrated their birthday after G. Neither F nor G celebrated their birthday on 28th of the month. The difference between the days of G and E to celebrate their birthday is 12. X celebrated his birthday immediately before E. No one celebrated their birthday between Y and F, who celebrated his birthday after Y. Z celebrated his birthday after H, who doesn’t celebrate his birthday before X. From above statements, Case-1 : Here G and E celebrated their birthday on 20th and 8th of the month respectively. X celebrated his birthday on 4th of the month. Y and F celebrated their birthday on 12th and 16th of the month respectively. Finally, H and Z celebrated their birthday on 24th and 28th of the month respectively. Thus all the given condition gets satisfied and we get the completed arrangement in Case- Case-2: Here G and E celebrated their birthday on 24th and 12th of the month respectively. X celebrated his birthday on 8th of the month. Y and F celebrated their birthday on 16th and 20th of the month respectively. As per last reference point, H doesn’t celebrate his birthday before X. Thus there is no other date left for H. Thus this case-2 becomes invalid and it can be eliminated.
Statements: N ≥ M ≥ O; U < N; V < O ≤ R
Conclusions:
I. V < N
II. R ≥ N
III. O < U
Statements: E = L ≤ G < I = H; E ≥ N < A; W ≥ P ≥ M > I
Conclusions:
I. E < W
II. A ≥ M
III. N < P
26. Statements: T @ V % Z # C & B $ S # E; W $ Z @ C
Conclusions : I. E @ Z ...
Statements: E > U > V ≥ K > F; E ≤ N = L < H
Conclusions: I. L > K II. U < H
Statements: M # N # O $ P & Q % R % S
Conclusions : I. Q @ S ...
Statements: A = B ≥ C > D, F > G = H ≥ J, D ≥ E ≥ I > F
Conclusions:
I. D ≥ H
II. I > J
III. G < A
Statements: A ≥ B > C < D, E ≥ F ≥ G, D = H ≥ E
Conclusion:
I. B > F
II. D ≥ G
III. C < G
Statements: S * C, C $ T, T # U, U % V
Conclusions :
I.V # T
II. C % U
III. S # U
IV. C % V...
Statements: N % X & F @ R $ S; Q % N # O
Conclusions:
I. S % X
II. N % F
III. Q @ R
...Statements: M $ K; K & N, N % R, R @ W
Conclusions:
I. W & K
II. K & W ...