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Box T is placed in even numbered position. Four boxes are placed between Box X and Box T. Box T is placed above Box X. Only two boxes are placed between the Box Z and Box V in which Box V is placed below Box Z. Box Z is placed in odd numbered position. Box Z is not placed above Box T. From above statements, Case 1: If Box T is placed at 8 th position and then Box X is placed at 3 rd position. Box Z is placed at 7 th position and Box V is placed at 4 th position. Case 1-S: If Box T is placed at 8 th position and then Box X is placed at 3 rd position. Box Z is placed at 5 th position and Box V is placed at 2 nd position. Case 2: If Box T is placed at 6 th position and then Box X is placed at 1 st position. Box Z is placed at 5 th position and Box V is placed at 2 nd position. Based on the above information, we get the initial table as follows Only one box is placed between the Box Y and Box W in which Box W is placed below Box Y. Box X is not placed above Box S. From above statements, Case 1 &2: Based on the above condition, there is no place for Box Y and Box W at s gap of 1 position. Hence, this case becomes invalid and it can be eliminated. Case 1-S: Based on the above condition, Box Y is placed at 6 th position and Box W is 4 th position. Given, Box X is not placed above Box S. Therefore, Box S is placed at 7 th position and Box U is placed at 1 st position. Thus we get the completed table,
(15 x 15 x 15 + 8 x 8 x 8)/(15 x 15 -15 x 8 + 8 x 8) = ?
If 27 (x+y)³ − 8(x−y)³ = (x + 5y) (Ax² + By² + Cxy), then what is the value of (A+B-C)?
Which of the following statements is correct?
I. If x = 12, y = –2 and z = –10, then x³ + y³
+ z³ = 360
II. If x + y = 48 an...
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
If ab = -15 and (a2 + b2) = 34, then find the value of (a – b).
If 112 ÷28 x 22 –12 x 6 ÷ 3 +12 = z, then find the value of z.
If {1/(y + 1) + 1/(y + 5)} = {1/(y + 2) + 1/(y + 4)}. Find the value of y
If x:y:z = 3:4:6, and (5x + 3z) = 132, then find the value of '3y'.